Question

Find out the value of K_c for each of the following equilibria from the value of K_p: 

Answer 1

The relation between K_p and K_c is given as: 

K_p = K_c (RT)^∆n 

(a) Here, 

∆n = 3 – 2 = 1 

R = 0.0831 barLmol^–1K^–1 

T = 500 K K_p = 1.8 × 10–2 

Now, 

K_p = K_c (RT) ^∆n 

(b) Here, 

∆n = 2 – 1 = 1 

R = 0.0831 barLmol^–1K^–1 

T = 1073 K 

K_p= 167 

Now, 

K_p = K_c (RT) ^∆n