Question

A sample of HI_(g) is placed in flask at a pressure of 0.2 atm. 

At equilibrium the partial pressure of HI_(g) is 0.04 atm. What is K_p for the given equilibrium? 

Answer 1

The initial concentration of HI is 0.2 atm. At equilibrium, it has a partial pressure of 0.04 atm. Therefore, a decrease in the pressure of HI is 0.2 – 0.04 = 0.16. The given reaction 

is;