The equilibrium constant for the following reaction is 1.6 ×105 at 1024 K.

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asked Oct 7, 2017 in Chemistry by jisu zahaan (28,760 points) 28 437 1096

The equilibrium constant for the following reaction is 1.6 ×105 at 1024 K. 

Find the equilibrium pressure of all gases if 10.0 bar of HBr is introduced into a sealed container at 1024 K. 

1 Answer

+1 vote
answered Oct 7, 2017 by sforrest072 (157,439 points) 63 448 1286
selected Oct 8, 2017 by sanjeev
 
Best answer

Given, 

for the reaction i.e., H2(g) + Br2(g) 2HBr(g) is 1.6x105 Therefore, for the reaction  2HBr(gH2(g) + Br2(g)   the equilibrium constant will be, 

Now, let p be the pressure of both H2 and Br2 at equilibrium. 

Now, we can write, 

Therefore, at equilibrium,

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