Given,
for the reaction i.e., H2(g) + Br2(g) ↔ 2HBr(g) is 1.6x105 Therefore, for the reaction 2HBr(g) ↔ H2(g) + Br2(g) the equilibrium constant will be,

Now, let p be the pressure of both H2 and Br2 at equilibrium.

Now, we can write,

Therefore, at equilibrium,
