Question

The ionization constant of acetic acid is 1.74 × 10^–5 . Calculate the degree of dissociation of acetic acid in its 0.05 M solution. Calculate the concentration of acetate ion in the solution and its pH. 

Answer 1

since Ka  >> Kw; 

Method 2 

Degree of dissociation, 

c = 0.05 M Ka = 1.74 × 10–5

Thus, concentration of CH3COO– = c.α 

Hence, the concentration of acetate ion in the solution is 0.00093 M and its Ph is 3.03.