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Given the standard electrode potentials,

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asked Oct 9, 2017 in Chemistry by jisu zahaan (28,760 points) ● 28 ● 438 ● 1106

Given the standard electrode potentials, 

K +/K = –2.93V, Ag+/Ag = 0.80V, Hg2+/Hg = 0.79V 

Mg2+/Mg = –2.37V. Cr3+/Cr = –0.74V 

Arrange these metals in their increasing order of reducing power. 

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answered Oct 9, 2017 by sforrest072 (157,439 points) ● 63 ● 451 ● 1306

Answer: We have

The lower the electrode potential, the stronger is the reducing agent. Therefore, the increasing order of the reducing power of the given metals is Ag < Hg < Cr < Mg < K. 

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Using the standard electrode potentials given in Table 3.1,
asked Dec 13, 2017 in Chemistry by sforrest072 (157,439 points)

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