Question

In the estimation of sulphur by Carius method, 0.468 g of an organic sulphur compound afforded 0.668 g of barium sulphate. Find out the percentage of sulphur in the given compound. 

Answer 1

Total mass of organic compound = 0.468 g [Given] 

Mass of barium sulphate formed = 0.668 g [Given] 

1 mol of BaSO₄ = 233 g of BaSO₄ = 32 g of sulphur 

Thus, 0.668 g of BaSO₄ contains (32X0.668/233g) of sulphur = 0.0917 g of sulphur 

Therefore, percentage of sulphur =(0.0197/0.468X100) = 19.59 % 

Hence, the percentage of sulphur in the given compound is 19.59 %.