(i) According to the equation of motion under gravity v2 − u2 = 2gs
Where,
u = Initial velocity of the ball
v = Final velocity of the ball
s = Height achieved by the ball
g = Acceleration due to gravity
At maximum height, final velocity of the ball is zero, i.e., v = 0 m/s and u = 49 m/s
During upward motion, g = − 9.8 m s−2
Let h be the maximum height attained by the ball.
Hence, using 2 − 2 = 2
We have, 02 − 492 = 2(−9.8)ℎ ⇒ ℎ = 49×49 / 2×9.8 = 122.5 m
Let t be the time taken by the ball to reach the height 122.5 m, then according to the equation of motion = +
We get,
0 = 49 + (−9.8) ⇒ 9.8 = 49 ⇒ = 49 / 9.8 = 5 s
But,
Time of ascent = Time of descent
Therefore, total time taken by the ball to return = 5 + 5 = 10 s