Question

A stone is thrown in a vertically upward direction with a velocity of 5 m/s. If the acceleration of the stone during its motion is 10 m/s² in the downward direction, what will be the height attained by the stone and how much time will it take to reach there?

Answer 1

Here we have, 

Initial velocity (u) = 5 m/s 

Final velocity (v) = 0 m/s 

Acceleration (a) = – 10 m/s² 

Height, i.e. Distance, s =? 

Time (t) taken to reach the height =? 

Thus, stone will attain a height of 1.25 m and time taken to attain the height is 0.5 s