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he activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x10-1 sec-1 . Calculate the frequency factor A.

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asked Dec 15, 2017 in Chemistry by sforrest072 (157,439 points) ● 63 ● 448 ● 1271

The activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x10-1 sec-1 . Calculate the frequency factor A.

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answered Dec 15, 2017 by mdsamim (213,225 points) ● 5 ● 10 ● 22
selected Dec 15, 2017 by sforrest072
 
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Given, Ea = 94.14 x103 J mol-1 , T = 40 + 273 = 313 K, K = 1.8 x 10-1 sec-1

 By using,

 A = antilog (10.9635) = 9.194 x1010 sec-l

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