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The activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x 10-1 sec-1.

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asked Dec 16, 2017 in Chemistry by sforrest072 (157,439 points) ● 61 ● 410 ● 937

The activation energy of a reaction is 94.14 KJ/mol and the value of rate constant at 40º C is 1.8 x 10-1 sec-1. Calculate the frequency factor A

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answered Dec 16, 2017 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Dec 16, 2017 by sforrest072
 
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Given, Ea = 94.14 x 103 J mol-1, T = 40 + 273 =313 K, K = 1.8 x 10-1 sec-1
By using,
 

A = antilog (10.9635) = 9.194 x 1010 sec-1

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