In PH3, P is sp3 hybridized. Three orbitals are involved in bonding with three hydrogen
atoms and the fourth one contains a lone pair. As lone pair-bond pair repulsion is stronger than bond pair-bond pair repulsion, the tetrahedral shape associated with sp3 bonding is changed to pyramidal. PH3 combines with a proton to form PH+4 in which the lone pair is absent. Due to the absence of lone pair in PH+4 , there is no lone pair-bond pair repulsion.
Hence, the bond angle PH+4 in is higher than the bond angle in PH3.
