Suggest reasons why the B–F bond lengths in BF3 (130 pm) and 4 − (143 pm) differ.

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asked Oct 12, 2017 in Chemistry by jisu zahaan (28,760 points) 28 436 1093

Suggest reasons why the B–F bond lengths in BF3 (130 pm) and BF4 (143 pm) differ. 

1 Answer

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answered Oct 12, 2017 by sforrest072 (157,439 points) 63 448 1286
selected Oct 12, 2017 by sanjeev
 
Best answer

The B–F bond length in BF3 is shorter than the B–F bond length in BF4 . BF3 is an electrondeficient species. With a vacant p-orbital on boron, the fluorine and boron atoms undergo pπ–pπ back-bonding to remove this deficiency. This imparts a double bond character to the B–F bond. 

This double-bond character causes the bond length to shorten in BF3 (130 pm). However, when BF3 coordinates with the fluoride ion, a change in hybridisation from sp2 (in BF3) to sp3 (in BF4 −) occurs. Boron now forms 4σ bonds and the double-bond character is lost. This accounts for a B–F bond length of 143 pm in BF4 ion. 

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