Question

If the first and the nth term of a G.P. are a and b, respectively, and if P is the product of n terms, prove that P² = (ab)ⁿ.

Answer 1

The first term of the G.P is a and the last term is b.

Therefore, the G.P. is a, ar, ar², ar³, … ar^n–1, where r is the common ratio.

b = ar^n–1 … (1)

P = Product of n terms

= (a) (ar) (ar²) … (ar^n–1)

= (a × a ×…a) (r × r² × …r^n–1)

= an r ^{1 + 2 +…(n–1)} … (2)

Here, 1, 2, …(n – 1) is an A.P.

∴1 + 2 + ……….+ (n – 1)