A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10^−7 C located at points

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asked Jan 2, 2018 in Physics by sforrest072 (157,439 points) 61 410 947
edited Mar 4, 2018 by Vikash Kumar

A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, − 15 cm) and B: (0, 0, + 15 cm), respectively. What are the total charge and electric dipole moment of the system?

1 Answer

+1 vote
answered Jan 2, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 4, 2018 by sanjeev
 
Best answer

Both the charges can be located in a coordinate frame of reference as shown in the given figure.

At A, amount of charge, qA = 2.5 × 10−7C
At B, amount of charge, qB = −2.5 × 10−7 C
Total charge of the system, q = qA + qB = 2.5 × 107 C − 2.5 × 10−7 C = 0
Distance between two charges at points A and B,
d = 15 + 15 = 30 cm = 0.3 m
Electric dipole moment of the system is given by, p
= qA × d = qB × d = 2.5 × 10−7 × 0.3
= 7.5 × 10−8 C m along positive z-axis
Therefore, the electric dipole moment of the system is 7.5 × 10−8 C m along positive z−axis.

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