There are two charges, q1= 5×10-8 C q2=-3×10-8 C
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.



⇒0.8=8r ⇒=0.1m =10cm
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges.
Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero, as shown in the following figure.



Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.