Two charges 5 × 10^−8 C and −3 × 10^−8 C are located 16 cm apart. At what point(s) on the line joining

+1 vote
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asked Jan 3, 2018 in Physics by sforrest072 (157,439 points) 60 410 937
edited Mar 4, 2018 by Vikash Kumar

Two charges 5 × 10−8 C and −3 × 10−8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.

1 Answer

+1 vote
answered Jan 3, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 4, 2018 by Vikash Kumar
 
Best answer

There are two charges, q1= 5×10-8 C q2=-3×10-8 C
Distance between the two charges, d = 16 cm = 0.16 m
Consider a point P on the line joining the two charges, as shown in the given figure.

⇒0.8=8r ⇒=0.1m =10cm
Therefore, the potential is zero at a distance of 10 cm from the positive charge between the charges. 

Suppose point P is outside the system of two charges at a distance s from the negative charge, where potential is zero, as shown in the following figure.

Therefore, the potential is zero at a distance of 40 cm from the positive charge outside the system of charges.

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