A point charge causes an electric flux of -1.0 × 10^3 Nm^2/C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge.

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asked Jan 3, 2018 in Physics by sforrest072 (157,439 points) 61 410 943
edited Mar 4, 2018 by Vikash Kumar

A point charge causes an electric flux of -1.0 × 103 Nm2/C to pass through a spherical Gaussian surface of 10.0 cm radius centered on the charge.
(a) If the radius of the Gaussian surface were doubled, how much flux would pass through the surface?
(b) What is the value of the point charge?

1 Answer

+1 vote
answered Jan 3, 2018 by mdsamim (213,225 points) 5 10 15
selected Mar 4, 2018 by Vikash Kumar
 
Best answer

(a) Electric flux, Φ = −1.0 × 103 N m2/C
Radius of the Gaussian surface, r = 10.0 cm
Electric flux piercing out through a surface depends on the net charge enclosed inside a body. It does not depend on the size of the body. If the radius of the Gaussian surface is doubled, then the flux passing through the surface remains the same i.e., -103 N m2/C.

(b) Electric flux is given by the relation

Where,

εo = Permittivity of free space = 8.854 × 10−12 N−1C2 m−2
q = Net charge enclosed by the spherical surface =
εoϕ​
= −1.0 × 103 × 8.854 × 10−12
= −8.854 × 10−9 C
= −8.854 nC

Therefore, the value of the point charge is −8.854 nC.

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