Question

Suppose that the particle in Exercise in 1.33 is an electron projected with velocity v_x= 2.0 × 10⁶ m s^−1. If E between the plates separated by 0.5 cm is 9.1 × 10² N/C, where will the electron strike the upper plate? (| e | =1.6 × 10⁻¹⁹ C, m_e = 9.1 × 10⁻³¹ kg.)

Answer 1

Velocity of the particle, vx = 2.0 × 10⁶ m/s
Separation of the two plates, d = 0.5 cm = 0.005 m
Electric field between the two plates, E = 9.1 × 10² N/C
Charge on an electron, q = 1.6 × 10⁻¹⁹ C
Mass of an electron, me = 9.1 × 10⁻³¹ kg
Let the electron strike the upper plate at the end of plate L, when deflection is s. Therefore,

Therefore, the electron will strike the upper plate after travelling 1.6 cm.