In Exercise 4.11 obtain the frequency of revolution of the electron in its circular orbit

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asked Jan 4, 2018 in Physics by sforrest072 (157,439 points) 63 448 1285
In Exercise 4.11 obtain the frequency of revolution of the electron in its circular orbit. Does the answer depend on the speed of the electron? Explain.

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answered Jan 4, 2018 by mdsamim (213,225 points) 5 10 22
edited Mar 4, 2018 by Vikash Kumar
 
Best answer

Magnetic field strength, B = 6.5 × 10−4 T
Charge of the electron, e = 1.6 × 10−19 C
Mass of the electron, me = 9.1 × 10−31 kg
Velocity of the electron, v = 4.8 × 106 m/s
Radius of the orbit, r = 4.2 cm = 0.042 m
Frequency of revolution of the electron =
Angular frequency of the electron =
ω = 2 πv
Velocity of the electron is related to the angular frequency as: v=rω 

In the circular orbit, the magnetic force on the electron is balanced by the centripetal force. 

Hence, we can write:

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