Ask a Question

A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm.

← Prev Question Next Question →
+1 vote
41 views
asked Jan 8, 2018 in Physics by sforrest072 (157,439 points) ● 63 ● 448 ● 1282

A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

1 Answer

+1 vote
answered Jan 8, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 22
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Focal length of the objective lens, fo = 144 cm

 Focal length of the eyepiece, fe = 6.0 cm

 The magnifying power of the telescope is given as:

The separation between the objective lens and the eyepiece is calculated as:

Hence, the magnifying power of the telescope is 24 and the separation between the objective lens and the eyepiece is 150 cm.

← Prev Question Next Question →

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...