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A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm.

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asked Jan 8, 2018 in Physics by sforrest072 (157,439 points) ● 61 ● 410 ● 941

A small telescope has an objective lens of focal length 144 cm and an eyepiece of focal length 6.0 cm. What is the magnifying power of the telescope? What is the separation between the objective and the eyepiece?

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answered Jan 8, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
edited Mar 5, 2018 by Vikash Kumar
 
Best answer

Focal length of the objective lens, fo = 144 cm

 Focal length of the eyepiece, fe = 6.0 cm

 The magnifying power of the telescope is given as:

The separation between the objective lens and the eyepiece is calculated as:

Hence, the magnifying power of the telescope is 24 and the separation between the objective lens and the eyepiece is 150 cm.

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