Calculate the (a) momentum, and (b) de Broglie wavelength of the electrons

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asked Jan 10, 2018 in Physics by sforrest072 (157,439 points) 61 410 947
Calculate the
(a) momentum, and
(b) de Broglie wavelength of the electrons accelerated through a potential difference of 56 V.

1 Answer

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answered Jan 10, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 10, 2018 by sforrest072
 
Best answer

Potential difference, V = 56 V
Planck’s constant, h = 6.6 × 10−34 Js
Mass of an electron, m = 9.1 × 10−31 kg
Charge on an electron, e = 1.6 × 10−19 C
(a) At equilibrium, the kinetic energy of each electron is equal to the accelerating
potential, i.e., we can write the relation for velocity (v) of each electron as:

The momentum of each accelerated electron is given as:
p = mv
= 9.1 × 10−31 × 4.44 × 106
= 4.04 × 10−24 kg m s−1

Therefore, the momentum of each electron is 4.04 × 10−24 kg m s−1
.

(b) De Broglie wavelength of an electron accelerating through a potential V, is given by
the relation:

Therefore, the de Broglie wavelength of each electron is 0.1639 nm.

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