A radioactive isotope has a half-life of T years. How long will it take the activity to reduce to a) 3.125%, b) 1% of its original value?

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asked Jan 10, 2018 in Physics by sforrest072 (157,439 points) 61 410 947
A radioactive isotope has a half-life of T years. How long will it take the activity to reduce to a) 3.125%, b) 1% of its original value?

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answered Jan 10, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 6, 2018 by Vikash Kumar
 
Best answer

Half-life of the radioactive isotope = T years
Original amount of the radioactive isotope = N0
(a) After decay, the amount of the radioactive isotope = N 

It is given that only 3.125% of N0 remains after decay. Hence, we can write:

Hence, the isotope will take about 5T years to reduce to 3.125% of its original value.

(b) After decay, the amount of the radioactive isotope = N 

It is given that only 1% of N0 remains after decay. Hence, we can write:

Hence, the isotope will take about 6.645T years to reduce to 1% of its original value.

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