A 1000 MW fission reactor consumes half of its fuel in 5.00 y.

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asked Jan 11, 2018 in Physics by sforrest072 (157,439 points) 61 410 938
edited Mar 6, 2018 by Vikash Kumar

A 1000 MW fission reactor consumes half of its fuel in 5.00 y. How much 23592U did it contain initially? Assume that the reactor operates 80% of the time, that all the energy generated arises from the fission of 23592U and that this nuclide is consumed only by the fission process.

1 Answer

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answered Jan 11, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 11, 2018 by sforrest072
 
Best answer

The reactor operates only 80% of the time.

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