For the curve y = 4x3 − 2x5, find all the points at which the tangents passes through the origin.

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asked Jan 20, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 943

For the curve y = 4x3 − 2x5, find all the points at which the tangents passes through the origin.

1 Answer

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answered Jan 20, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 20, 2018 by sforrest072
 
Best answer

The equation of the given curve is y = 4x3 − 2x5.

Therefore, the slope of the tangent at a point (x, y) is 12x2 − 10x4. The equation of the tangent at (x, y) is given by,

When the tangent passes through the origin (0, 0), then X = Y = 0. Therefore, equation (1) reduces to:

When x = 1, y = 4 (1)3 − 2 (1)5 = 2.
When x = −1, y = 4 (−1)3 − 2 (−1)5 = −2.
Hence, the required points are (0, 0), (1, 2), and (−1, −2).

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