Find the points on the curve y = x^3 at which the slope of the tangent is equal to the y-coordinate of the point.

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asked Jan 20, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949

Find the points on the curve y = x3 at which the slope of the tangent is equal to the y-coordinate of the point.

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answered Jan 20, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 7, 2018 by faiz
 
Best answer

The equation of the given curve is y = x3.

The slope of the tangent at the point (x, y) is given by,

When the slope of the tangent is equal to the y-coordinate of the point, then y = 3x2.
Also, we have y = x3.

∴3x2 = x3
∴ x2 (x − 3) = 0
∴ x = 0, x = 3

When x = 0, then y = 0 and when x = 3, then y = 3(3)2 = 27.
Hence, the required points are (0, 0) and (3, 27).

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