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Find the slope of the tangent to curve y = x^3 − x + 1 at the point whose x-coordinate is 2.

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asked Jan 22, 2018 in Mathematics by sforrest072 (157,439 points) ● 61 ● 410 ● 949
edited Mar 7, 2018 by faiz

Find the slope of the tangent to curve y = x3 − x + 1 at the point whose x-coordinate is 2.

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answered Jan 22, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Jan 22, 2018 by sforrest072
 
Best answer

It is given that x0 = 2.
Hence, the slope of the tangent at the point where the x-coordinate is 2 is given by,

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