The equations of the given curves are given as 
Putting x = y2 in xy = k, we get:

On differentiating xy = k with respect to x, we have:

We know that two curves intersect at right angles if the tangents to the curves at the
point of intersection i.e., at
are perpendicular to each other.
This implies that we should have the product of the tangents as − 1.
Thus, the given two curves cut at right angles if the product of the slopes of their
respective tangents at
is −1.

Hence, the given two curves cut at right angels if 8k2 = 1.