Prove that the curves x = y^2 and xy = k cut at right angles if 8k^2 = 1. [Hint: Two curves intersect

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asked Jan 20, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949

Prove that the curves x = y2 and xy = k cut at right angles if 8k2 = 1. [Hint: Two curves intersect at right angle if the tangents to the curves at the point of intersection are perpendicular to each other.]

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answered Jan 20, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 20, 2018 by sforrest072
 
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The equations of the given curves are given as 

Putting x = y2 in xy = k, we get:

On differentiating xy = k with respect to x, we have:

We know that two curves intersect at right angles if the tangents to the curves at the

point of intersection i.e., at  are perpendicular to each other.

This implies that we should have the product of the tangents as − 1.
Thus, the given two curves cut at right angles if the product of the slopes of their
respective tangents at is −1.

Hence, the given two curves cut at right angels if 8k2 = 1.

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