How can three resistors of resistance 2Ω,3Ω and 6Ω be connected to give a total resistance of (i)4Ω, (ii)1Ω?

0 votes
32 views
asked Jan 21, 2018 in Physics by Kundan kumar (49,132 points) 34 436 1368

How can three resistors of resistance 2Ω,3Ω and 6Ω be connected to give a total resistance of (i)4Ω, (ii)1Ω?

1 Answer

0 votes
answered Jan 21, 2018 by Vikash Kumar (144,729 points) 8 11 26
selected Jan 21, 2018 by Kundan kumar
 
Best answer

(i) As the total resistance (equivalent resistance) is 4Ω, the 6Ω resistor cannot be in series. So, it must be in parallel with some other resistors. In a parallel connection, the equivalent resistance (4Ω) has to be less than all the resistances. So, the resistors of 2Ω and 3Ω cannot be in parallel at one time with 6Ω.

So, the resistors have to be in a mixed combination' Let
us consider the combination shown in the figure. The equivalent resistance between B and C (which are in parallel)

The resistance between A and D = 2Ω + 2Ω = 4 Ω.
So, the combination shown in the figure is true.

(ii) Here, R1=2Ω,R2 =3Ω,R3 = 6Ω, and R =1Ω
Since the equivalent resistance of the combination is of lesser value than any of the resistors of the combination, it is clear that the resistors should be connected in parallel. It can be further confirmed by using the formula

Therefore, resistors should be connected in parallel.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

...