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Show how you would connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (i) 9Ω (ii) 4Ω.

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asked Jan 22, 2018 in Physics by Kundan kumar (49,132 points) ● 34 ● 378 ● 1010

Show how you would connect three resistors, each of resistance 6Ω, so that the combination has a resistance of (i) 9Ω (ii) 4Ω.

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answered Jan 22, 2018 by Vikash Kumar (144,729 points) ● 8 ● 11 ● 21
selected Jan 23, 2018 by Kundan kumar
 
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(i) In order to get a resistance of 9‎Ω, We connect the given resistors (each of resistance of 6‎Ω) in the following way. Resistance between B and C

Resistance of the combination = 6‎Ω + 3‎Ω = 9‎Ω

(ii) In order to get a resistance of 4‎Ω, we connect two resistors in series and third in parallel as shown in the figure.
Resistors AB and BC are in series, therefore.

Rs =6‎Ω+6‎Ω=12‎Ω

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