Question

Find the point on the x-axis which is equidistant from (2, –5) and (–2, 9).

Answer 1

Answer:
We have to find a point on x-axis. Therefore, its y-coordinate will be 0.
Let the point on x-axis be (x,0)
(x - 2)² + 25 = (x - 2)² + 81
x² + 4 - 4x + 25 = x² + 4 + 4x + 81
8x = 25 -81
8x = -56
x = -7
Therefore, the point is ( - 7, 0).