Question

Find the values of y for which the distance between the points P(2, – 3) and Q(10, y) is 10 units.

Answer 1

Answer:
It is given that the distance between (2, - 3) and (10, y) is 10.
64 + (y + 3)² = 100
(y +3)² = 36
y + 3 = ±6
y + 3 = +6 or y + 3 = -6
Therefore, y = 3 or -9