Question

The point on the curve x² = 2y which is nearest to the point (0, 5) is

(A)   (2√2,4)                (B)    (2√2,0)

(c)     (0,0)                 (D)    (2,2)

Answer 1

The given curve is x² = 2y.

Hence, the point on the curve x² = 2y which is nearest to the point (0, 5) is (±2√2,4)
The correct answer is A.