The normal at the point (1, 1) on the curve 2y + x^2 = 3 is (A) x + y = 0 (B) x − y = 0

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asked Jan 23, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949

The normal at the point (1, 1) on the curve 2y + x2 = 3 is
(A) x + y = 0 (B) x − y = 0
(C) x + y + 1 = 0 (D) x − y = 1

1 Answer

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answered Jan 23, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 23, 2018 by sforrest072
 
Best answer

The equation of the given curve is 2y + x2 = 3.
Differentiating with respect to x, we have:

The slope of the normal to the given curve at point (1, 1) is  

Hence, the equation of the normal to the given curve at (1, 1) is given as:

The correct answer is B.

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