The normal to the curve x^2 = 4y passing (1, 2) is (A) x + y = 3 (B) x − y = 3

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asked Jan 23, 2018 in Mathematics by sforrest072 (157,439 points) 63 447 1245

The normal to the curve x2 = 4y passing (1, 2) is
(A) x + y = 3 (B) x − y = 3
(C) x + y = 1 (D) x − y = 1

1 Answer

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answered Jan 23, 2018 by mdsamim (213,225 points) 5 10 21
selected Jan 23, 2018 by sforrest072
 
Best answer

The equation of the given curve is x2 = 4y.
Differentiating with respect to x, we have:

The slope of the normal to the given curve at point (h, k) is given by, 

From equation (i), we have:

Hence, the equation of the normal is given as:

The correct answer is A.

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