Find the equation of the plane through the intersection of the planes 3x-y+2z-4=0 and x+y+z-2=0 and the point (2,2,1)

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asked Jan 25, 2018 in Mathematics by sforrest072 (157,439 points) 61 411 949
Find the equation of the plane through the intersection of the planes

3x-y+2z-4=0 and x+y+z-2=0 and the point (2,2,1)

1 Answer

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answered Jan 25, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 25, 2018 by sforrest072
 
Best answer

The equation of any plane through the intersection of the planes, 3x − y + 2z − 4 = 0 and x + y + z − 2 = 0, is

The plane passes through the point (2, 2, 1). Therefore, this point will satisfy equation (1).

This is the required equation of the plane.

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