Find the coordinates of the point where the line through (3, −4, −5) and (2, − 3, 1) crosses the plane 2x + y + z = 7).

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asked Jan 25, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 949
Find the coordinates of the point where the line through (3, −4, −5) and (2, − 3, 1) crosses the plane 2x + y + z = 7).

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answered Jan 25, 2018 by mdsamim (213,225 points) 5 10 15
edited Mar 7, 2018 by Vikash Kumar
 
Best answer

It is known that the equation of the line passing through the points, (x1, y1, z1) and (x2,y2, z2),

Since the line passes through the points, (3, −4, −5) and (2, −3, 1), its equation is given by,

Therefore, any point on the line is of the form (3 − k, k − 4, 6k − 5).
This point lies on the plane, 2x + y + z = 7

Hence, the coordinates of the required point are (3 − 2, 2 − 4, 6 × 2 − 5) i.e., (1, −2, 7).

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