Let the side of the larger square be x.
Let the side of the smaller square be y.
APQ x2+y2 = 468
Cond. II
4x-4y = 24
=> x – y = 6
=> x = 6 + y
x2 + y2 = 468
=> (6+y)2 +y2 = 468
on solving we get y = 12
=> x = (12+6) = 18 m
Therefore, sides are 18m & 12m.