Ask a Question

The sum of the areas of two squares is 468 m^2 . If the difference of their perimeters is 24 m, find the sides of the two squares.

← Prev Question Next Question →
0 votes
31 views
asked Feb 1, 2018 in Mathematics by Kundan kumar (49,132 points) ● 34 ● 381 ● 1015

The sum of the areas of two squares is 468 m2 . If the difference of their perimeters is 24 m, find the sides of the two squares.

1 Answer

0 votes
answered Feb 1, 2018 by Vikash Kumar (144,729 points) ● 8 ● 11 ● 21
 
Best answer

Let x be the length of the side of the first square and y be the length of side of the second square.

Putting the value of x in terms of y from equation (ii), in equation (i), we get

← Prev Question Next Question →

Related questions

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

One Thought Forever

“There is a close connection between getting up in the world and getting up in the morning.“
– Anon
~~~*****~~~

Related questions

© 2017 Sarthaks eConnect
Managed by Sarthaks Digitizing India
...