Maximise Z = 3x + 2y subject to x+2y≤ 10, 3x+y≤15,x,y≥ 0

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asked Jan 25, 2018 in Mathematics by sforrest072 (157,439 points) 61 411 949

Maximise Z = 3x + 2y
subject to x+2y≤ 10, 3x+y≤15,x,y≥ 0

1 Answer

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answered Jan 25, 2018 by mdsamim (213,225 points) 5 10 15
selected Jan 25, 2018 by sforrest072
 
Best answer

The feasible region determined by the constraints, x + 2y ≤ 10, 3x + y ≤ 15, x ≥ 0, and y ≥ 0, is as follows.

The corner points of the feasible region are A (5, 0), B (4, 3), and C (0, 5).
The values of Z at these corner points are as follows.

Therefore, the maximum value of Z is 18 at the point (4, 3).

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