Solve for x and y. 6/(x-1) -3/(y-2) =1; 5/(x-1)+1/(y-2) =2 where x ≠1,y ≠2

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asked Jan 30, 2018 in Mathematics by sforrest072 (157,439 points) 63 448 1264

Solve for x and y. 

6/(x-1) -3/(y-2) =1;

5/(x-1)+1/(y-2) =2 where x ≠1,y ≠2

1 Answer

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answered Jan 30, 2018 by mdsamim (213,225 points) 5 10 21
selected Jan 30, 2018 by sforrest072
 
Best answer

Putting this value in equation (l) we get

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