Without using trigonometric tables, prove that: (sec^2θ-cot^2(90º-θ))/(cosec^2 67º-tan^2 23º)+(sin^2 40º+sin^2 50º)=2

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answered Feb 5, 2018 by Vikash Kumar (144,729 points)

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Without using trigonometric tables, prove that: (sec^2θ-cot^2(90º-θ))/(cosec^2 67º-tan^2 23º)+(sin^2 40º+sin^2 50º)=2

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