Prove that tan9-tan27-tan63+tan81=4

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asked Feb 10, 2018 in Mathematics by Ankit Agarwal (28,847 points) 7 32 67

Prove that tan9-tan27-tan63+tan81=4

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+1 vote
answered Feb 10, 2018 by Ankit Agarwal (28,847 points) 7 32 67
 
Best answer

Solution:

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answered Feb 10, 2018 by Annu Priya (18,055 points) 24 45 82

We have tan9° - tan27° - tan63° + tan81° = 4 

LHS = tan9° + tan81° -( tan27° + tan63°)

= {sin9°/cos9° + sin81°/cos81°} - { sin27°/cos27° + sin63°/cos63° }

={ sin9°.cos81°+ sin81°.cos9°}/cos9°.cos81° - { sin27°.cos63° + cos27°.sin63°}/cos27°.cos63°

=sin(9°+ 81°)/cos9°.cos81° - sin(27° +63°)/cos27°.cos63°

= 1/cos9°.cos81° - 1/cos27°.cos63°

=2/(2cos9°.cos81°) - 2/(2cos27°.cos63°)

= 2/{ cos(9° + 81°) + cos(81 -9°) - 2/{ cos(27°+ 63°) + cos(63° -27°)}

=2/cos72° - 2/cos36° 

= 2( cos36° - cos72°)/cos36°.cos72°

= 2( 2sin54°.sin18°)/cos36°.cos72°

=4sin54°.sin18°/cos36°.cos72°

=4sin(90-36°).sin(90°-18°)/cos36°.cos72°

=4cos36°.cos72°/cos36°.cos72°

= 4 = RHS

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