The areas of two similar triangles are 81 cm^2 and 49 cm^2 respectively.

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asked Feb 13, 2018 in Mathematics by sforrest072 (157,439 points) 61 410 942

The areas of two similar triangles are 81 cm2 and 49 cm2 respectively. Find the ratio of their corresponding heights. What is the ratio of their corresponding medians?

1 Answer

+1 vote
answered Feb 13, 2018 by mdsamim (213,225 points) 5 10 15
selected Feb 13, 2018 by sforrest072
 
Best answer

We have,
ΔABC ~ ΔPQR
Area (ΔABC) = 81 cm2,
Area (ΔPQR) = 49 cm2
And AD and PS are the altitudes
By area of similar triangle theorem

 Since, the ratio of the area of two similar triangles is equal to the ratio of the squares of the squares of their corresponding altitudes and is also equal to the squares of their corresponding medians.
Hence, ratio of altitudes = Ratio of medians = 9 : 7

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