Question

The areas of two similar triangles are 100 cm² and 49 cm² respectively. If the altitude the bigger triangle is 5 cm, find the corresponding altitude of the other.

Answer 1

Area(ΔABC) = 100 cm²,
Area (ΔPQR) = 49 cm²
AD = 5 cm
And AD and PS are the altitudes
By area of similar triangle theorem

in Δ and Δ P Q S
∠B = ∠Q [ΔABC ~ ΔPQR]
∠ADB = ∠PSQ [Each 90°]
Then, ΔABD ~ ΔPQS [By AA similarity]