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Prove that (secθ+cosθ)(secθ-cosθ)=tan^2θ+sin^2θ

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asked Feb 14, 2018 in Mathematics by Kundan kumar (49,132 points) ● 34 ● 384 ● 1028
edited Feb 14, 2018 by Vikash Kumar

Prove that (secθ+cosθ)(secθ-cosθ)=tan2θ+sin2θ

Prove that (sec theta+cos theta)(sec theta-cos theta)=tan2 theta+sin2theta

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answered Feb 14, 2018 by Vikash Kumar (144,729 points) ● 8 ● 11 ● 21
 
Best answer

=LHS = RHS Hence proved

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