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If A, B, C are the interior angles of a ΔABC, show that: sin (B+C)/2 = cos A/2

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asked Feb 16, 2018 in Mathematics by sforrest072 (157,439 points) ● 61 ● 410 ● 943
edited Mar 6, 2018 by faiz
If A, B, C are the interior angles of a ΔABC, show that:

sin (B+C)/2 = cos A/2

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answered Feb 16, 2018 by mdsamim (213,225 points) ● 5 ● 10 ● 15
selected Feb 16, 2018 by sforrest072
 
Best answer

A + B + C = 180

B – C = 180 –A/2

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