Consider a gold nucleaus to be sphere of radius 6.9 fermi in which protons and nuetrons are distributed.

Question

Find the force of repulsion between two protons situated at largest seperation. Why do these protons not fly apart under this repulsion ?

Answer 1

We can solve it by using Coulomb's Law,

The electromagnetic force of repulsion between positive protons in the nucleus is overcome by the strong nuclear force between protons and neutrons. This force is larger than the previous one and hence holds the nucleus together.So, these protons not fly apart under this repulsion