Question

Compute the bulk modulus of water from the following data: Initial volume = 100.0 litre, Pressure increase = 100.0 atm (1 atm = 1.013 × 10⁵ Pa), Final volume = 100.5 litre. Compare the bulk modulus of water with that of air (at constant temperature). Explain in simple terms why the ratio is so large.

Answer 1

Initial volume, V₁ = 100.01 = 100.0 × 10 ^–3 m³
Final volume, V₂ = 100.5 1 = 100.5 ×10 ^–3 m³
Increase in volume, ΔV = V₂ – V₁ = 0.5 × 10^–3 m³
Increase in pressure, Δp = 100.0 atm = 100 × 1.013 × 10⁵ Pa